4x^2+300x-9000=0

Solution for 4x^2+300x-9000=0 equation:

4x^2+300x-9000=0

a = 4; b = 300; c = -9000;
Δ = b2-4ac
Δ = 3002-4·4·(-9000)
Δ = 234000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{234000}=\sqrt{3600*65}=\sqrt{3600}*\sqrt{65}=60\sqrt{65}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-60\sqrt{65}}{2*4}=\frac{-300-60\sqrt{65}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+60\sqrt{65}}{2*4}=\frac{-300+60\sqrt{65}}{8}
$